The control by 1 individual of the WoT is necessary to use a free money. So if you have a horizon of Distance 3, to have a 99% confidence for a community1, concerning another community2, the distance from 1 human to another is unknown, and so the meta-money including M1 and M2, is not a free money, and it’s a violation of freedom to pretend you can fix a rate between them.
that must not be the case, depends on the protocol. the protocol could require that the trust distance between the members of two communities that trust each other is not more then n
And if it exist 1 man, who accepted the rules of D1max for M1, you have n > Dmax by definition, since n = D1max + D2max, so you break the contract. You have no right to break the contract accepted by another man.
sorry i could not follow, please define what is D1 and M1 and Dmax.
i guess your example is analog to the same situation as if currently one member breaks the distance rule in the web of trust.
if this happens with the current ucoin protocol the member will loose his membership after a certain time period and therefore will not receive any universal dividend anymore. but he could still do with the coins he has what he want to do. so no contract will be broken.
by the way with the current ucoin protocol where trust relations can be one way. your contract with the max distance between two members will be broken very easily.
If you try to connect two free moneys, of 2 communities, C1 & C2, composed by N1 & N2 members, you have distances maximum D1max in (C1,M1,N1,D1max), and a D2max in (C2,M2,N2,D2max).
So a man H1 of C1 cannot be sure there are N2 members in C2 following the rules he accepted, he cannot agree to recognize a man in C2, that will be at an unknown distance from him (out of C1 is “unknown” distance for him), and even if there is a connection thru some connections between C1 and C2 (somme man part of C1 and C2), it will be a distance Dmax >= D1max + D2max, that is > D1max, so the money (M1+M2) will not be a free money with D1max distance between all men.